Question

4. Find the anglexit EF I CDGH || BC and AB | ED I FG in the given figure. ​

Answer 1

Answer:

In the given figure we have to prove that Δ ADE and Δ FGC are similar.

Now from Δ ADE and Δ GFC we have,

∠AED=∠GFC [right-angles],

∠DAE=∠FGC [ ∵ AD∥GF andAC intersector, similar angles].

Then ∠ADE=∠GCF [Remaining angles equal by 180

∘

rule].

∴ΔADE is similar to ΔGFC.[By AA test] [henceproved]

Answer 2

Answer:

Step-by-step explanation:

Please see attachment .

Hope this will help you