Math, asked by gayatri2288, 2 months ago

4. Find the approximate sum to the nearest ten:
(i) (72 + 37)
(ii) (246 + 348)
(iii) (2,538 + 6,274)
(iv) (4,782 + 2,345)​

Answers

Answered by amarsinghq077
2

Answer:

1. 70 + 40 = 110

2. 250 + 350 = 600

3. 2540 + 6270 = 8810

4. 4780 + 2340 = 7120

Step-by-step explanation:

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Answered by gayukumari137
1

Answer:

Ans (i) 110

(ii) 610

(iii) 8,810

(iv) 7,130

Step-by-step explanation:

(i) 72 - 70

37- 40

Approximate sum - 70+40= 110

(ii) 264 - 260

348 - 350

Approximate sum - 260+350=610

(iii) 2,538 - 2,540

6,274 - 6,270

Approximate sum - 2,540+6,270=8,810

(iv) 4,782 - 4,780

2,345 - 2,350

Approximate sum - 4,780+2,350=7,130.

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