4. Find the area of the quadrilateral whose vertices, taken in order, are (-4,-2)
(3,-5) and (2,-3)and (2,3.)
Answers
Answer:
Area of the Quadrilateral is 24 units².
Step-by-step explanation:
Given:
Vertex of Quadrilateral say ABCD
Coordinates of the vertices are A( -4 , -2 ) , B ( 3 , -5 ) , C( 2 , -3 ) and D( 2 , 3 )
To find: Area of the Quadrilateral.
We know that a diagonal break the quadrilateral in two triangles.
Draw diagonal AC. we get ΔABC and ΔADC
Area of Quadrilateral = Area of ΔABC + Area of ΔADC
Area of triangle is given as follows when coordinates are given,
Area of ΔABC
Area of ΔADC
Area of the Quadrilateral = 11/2 + 37/2 = 48/2 = 24 units²
Therefore, Area of the Quadrilateral is 24 units².