Question

4. Find the average of the smallest and the greatest three-digit numbers that are
divisible by 13.
(1) 546 (2) 1092 (3) 104 (4) 98​

Answer 1

(1) 546 is correct answer

Explanation

if we cnsider a number 100 divided by 13 and remainder is 9

100+(13-9)=104 is smallest number

Now ,consider a number 999 divided by 13 we get remainder 11

so 999-11=988 is largest number

∴average = $(\frac{104+988}{2})\:=\: 546$ans

Answer 2

Step-by-step explanation:

(1) 546 is correct answer

Explanation

if we cnsider a number 100 divided by 13 and remainder is 9

100+(13-9)=104 is smallest number

Now ,consider a number 999 divided by 13 we get remainder 11

so 999-11=988 is largest number

∴average = (\frac{104+988}{2})\:=\: 546(

2

104+988

)=546 ans