Question

4. Find the co-ordinates of points on the x-axis
whic are at a distance of 17 units from the
point (11, -8)​

Answer 1

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Let P(x,0) be the point on the x-axis which is at a distance of 2√5 units from the point A(7,-4)

By applying Distance formula,

AP = 2√5

⇒ AP² = (2√5)² = 20 [Squaring on both sides]

⇒ (x - 7)² + (0+4)² = 20

⇒ (x-7)² = 4

⇒ x-7 = 2 or -2

⇒ x = 9 or x = 5

Hence, the required point is P(5,0) or P'(9,0)

There can be two such points on the x-axis.

Answer 2

Hello friends

I am here to help you

Let P(x,0) be the point on the x-axis which is at a distance of 2√5 units from the point A(7,-4)

By applying Distance formula,

AP = 2√5

⇒ AP² = (2√5)² = 20 [Squaring on both sides]

⇒ (x - 7)² + (0+4)² = 20

⇒ (x-7)² = 4

⇒ x-7 = 2 or -2

⇒ x = 9 or x = 5

Hence, the required point is P(5,0) or P'(9,0)

There can be two such points on the x-axis.