4. Find the compound interest, correct to the
nearest rupee, on 2,400 for 5/2
years at
5 percent per annum.
Answers
Answered by
2
Answer:
Principle=2400,time=
2
5
,rateofinterest=5%
Amount=P(1+
100
R
)
t
⇒2400(1+
100
5
)
2
5
⇒2400×
100
105
×
100
105
×
100
102.5
⇒
100000
24×105×105×1025
⇒
100000
271215000
⇒2712.15Rs.
C.I.=2712.15−2400=312Rs.
Step-by-step explanation:
Answered by
2
Answer:
C. I. =p(1+r/100)time-p
Step-by-step explanation:
2400(1+5/100)-24003
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