4. Find the compound interest, correct to the
nearest rupee, on 2,400 for
years at
5 percent per annum.
? 2
Answers
Answered by
2
step by step :
We first calculate the C.I. for first 2 years and then the S.I. next
2
1
year.
For ,
N=2years
R=5 %
=>P=Rs2,400
And on interest being compounded we have,
Amount=P(1+
100
R
)
N
=2,400×(1+
100
5
)
2
=2,400×1.05
2
=Rs2,646
So, C.I for first 2 years =.=A−P=Rs2,646=Rs2,400=Rs246
This, Rs2,646 is the principal for the next
2
1
year.
So, S.I.=
100
PNR
=
100
2,646×
2
1
×5
=Rs66.15
Thus, total interest =Rs246+Rs66.15=Rs312.15
To the nearest rupee , it is Rs312
Answer:
Rs. 312
Answered by
0
Answer:
12000 is the answer
Step-by-step explanation:
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