Question

4. Find the compound interest for Rupees 6250 at 16% PA.for 2 years compounded
annually.


say answer by solving or sending pic​

Answer 1

$\bf \: \underline{ Given }\: :$ ↴

$\sf \: Principal \: : \: Rs. \: 6250$

$\sf \: Rate \: of \: Interest \: : \: 16 \%$

$\sf \: Time \: : \: 2\: Years.$

$\bf \: \underline{To \: find }\: :$ ↴

$\sf \: We \: have \: to \: find \: the \: Compound \: Interest.$

$\sf \: \red{ \bigstar} \underline{\: So, \: Let's \: Start \: } \: \red{\bigstar }$

$\sf \: First \: of \: all \: we \: are \: going \: to \: find \: the \: amount..$

$\pink{ \underline{\boxed{ \sf \: Amount \: : P \: \bigg(\: 1 + \frac{R}{100} \: \bigg ) ^{n} }}}$

$\sf \: \underline{Putting \: the \: values }$

$\sf \: Amount \rightarrow \: 6250 \: \bigg(\: 1 + \dfrac{16}{100} \bigg ) ^{2}$

$\sf \: Amount \rightarrow \: 6250 \: \bigg(\: 1 + \dfrac{4}{25} \bigg ) ^{2}$

$\sf \: Amount \rightarrow \: 6250 \: \bigg( \dfrac{25 + 4}{25} \bigg ) ^{2}$

$\sf \: Amount \rightarrow \: 6250 \: \bigg( \dfrac{29}{25} \bigg ) ^{2}$

$\sf \: Amount \rightarrow \: 6250 \: \bigg( \dfrac{29}{25} \times \dfrac{29}{25} \bigg)$

$\sf \: Amount \rightarrow \: 6250 \: \times \dfrac{841}{625}$

$\pink{\sf \: Amount \rightarrow \:8410}$

$\sf \: \underline{Now, \: we \: will \: find \: the \: Compound \: Interest. }$

$\green{ \underline{ \boxed{ \sf \green{CI = Amount \: - Principal }}}}$

$\sf \: \underline{Putting \: the \: values }$

${ \sf {CI = 8410\: - \: 6250 }}$

$\purple{{ \sf {CI = Rs. \: 2160 }}}$

Answer 2

Given :

• Principal (P) = Rs 6250
• Time (n) = 2 years
• Rate (R) = 16% per annum

To Find :

• Compound interest

Formulas :

$\red \bigstar \: {\underline \orange {\boxed{\mathcal {\pmb{ \color{aqua}\quad Amount \: = \: Principal \: \times \bigg(\:1 \: + \: \dfrac{Rate}{100}\bigg)^{n}\quad}}}}}$

$\red \bigstar \: {\underline \orange {\boxed{\mathcal {\pmb{\color{aqua}\quad Compound \: Interest \: = \: Amount \: - \: Principal \quad}}}}}$

Solution :

${:} \longrightarrow \sf \: Amount \: = \: Principal \: \times \bigg(\:1 \: + \: \dfrac{Rate}{100}\bigg)^{n} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 6250 \: \times \bigg(\:1 \: + \: \dfrac{16}{100}\bigg)^{2} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 6250 \: \times \bigg(\dfrac{116}{100}\bigg)^{2} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 6250\: \times \: \dfrac{116}{100} \: \times \: \dfrac{116}{100} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 625\cancel{0} \: \times \: \dfrac{116}{10 \cancel{0}} \: \times \: \dfrac{116}{100} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: \dfrac{625 \: \times \: 116 \: \times \: 116}{10 \: \times \: 100} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: \dfrac{625 \: \times \: 13456}{1000} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: \dfrac{625 \: \times \: 13456}{1000} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: \dfrac{8410000}{1000} \\ \\ {:} \longrightarrow \underline{\boxed{ \color{lime}\sf \: Amount \: = \: Rs \: 8410 }} \color{navy} \: \: \bigstar$

━━━━━━━━━━

$\longmapsto {\pmb{ Compound \: Interest \: = \: Amount \: - \: Principal} } \\ \\ \longmapsto {\sf{ Compound \: Interest \: = \: 8410 \: - \: 6250} } \\ \\ \longmapsto \underline{\boxed{\pmb{ \red{ Compound \: Interest \: = \:Rs \: 2160} }}}$

━━━━━━━━━━

$\qquad \therefore\: \sf{ Amount \: = \underline {\underline{ Rs \: 8410}}}$

$\qquad \therefore\: \sf{ Compound \: Interest\: = \underline {\underline{ Rs \: 2160}}}$

━━━━━━━━━━