Question

4)Find the compound interest
on Rs.12600 for 2 years at 10%
per annum compunded
annually? *​

Answer 1

Answer:

Answer

We have,

A=P(1+

100

R

)

n

Here, P=Rs.12600,R=10,n=2

Therefore,

A=12600(1+

100

10

)

2

=12600(

10

11

)

2

=12600×

10

11

×

10

11

=Rs.15246

CI=A−P=Rs.15246−Rs.12600=Rs.2646

Answer 2

Given :-

• Principal amount is Rs 12,600  
• Rate of interest is 10 %
• Time is 2 years  

To Find :-

• Compound Interest  

Solution :-

~Here, we’re given the principal , rate of interest and time for which the money is invested and we need to find the Compound Interest ( CI ) after the given time. We can easily find the amount by putting the values in it’s formula and then Compound Interest.  

_____________

Here,  

• The principal  ( P ) is Rs. 12,600

• The rate ( R ) is 10 %  

• The time ( n )  is 2 years  

• The amount will be ( A )  

• Compound Interest be ( CI )  

_____________

As we know that ,

$\boxed{\sf{ \maltese \;\; A = P \bigg\{ 1 + \dfrac{R}{100} \bigg\}^{n} }}$

$\boxed{ \sf { \maltese \;\; CI = A -P }}$  

Finding the Amount :-

$\sf \dashrightarrow A = 12,600 \bigg\{ 1 + \dfrac{10}{100} \bigg\}^{2}$

$\sf \dashrightarrow A = 12,600 \bigg\{ \dfrac{11}{10} \bigg\}^{2}$

$\sf \dashrightarrow A = 12,600 \times \dfrac{11}{10} \times \dfrac{11}{10}$

$\sf \dashrightarrow A = 126 \times 11 \times 11$

$\boxed{\bf{ \bigstar \;\; Amount = Rs. \; 15,246 }}$

Finding the Compound Interest :-

$\sf \dashrightarrow CI = Rs \; 15,246 - Rs \; 12,600$

$\boxed{ \bf { \bigstar \;\; Compound\;Interest = Rs. \; 2,646 }}$

_____________

Hence,  

• The compound interest is Rs. 2,646