Math, asked by VijayaLaxmiMehra1, 1 year ago

4. Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2, – 3)

and B is (1, 4).

Standard:- 10

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Answers

Answered by siddhartharao77
24
Let the coordinates of point A be (x,y).

Given that Midpoint of AB is (2,-3).

The midpoint formula is:

= > (x1 + x2/2), (y1 + y2)/2

(1).

= > (x + 1)/2 = 2

= > x + 1 = 4

= > x = 3.



(2) 

= > (y + 4)/2 = -3

= > y + 4 = -6

= > y = -10.



Therefore the coordinates of point A is (3,-10).


Hope this helps!

siddhartharao77: :-)
VijayaLaxmiMehra1: Can you solve the problem of physics numerical which I have posted just now?
siddhartharao77: i dont know physics much sis
VijayaLaxmiMehra1: Oh Ok No problem bro!!
VijayaLaxmiMehra1: u not find the coordinate of a point B in ques there is mentioned
siddhartharao77: Sis, In (1), i wrote x + 1, can u see, Here 1 is the coordinate in B.
VijayaLaxmiMehra1: Yeah :-)
Answered by shinayu2276
1

Answer:

HOPE THIS WILL HELP YOU..

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