4. Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2, – 3)
and B is (1, 4).
Standard:- 10
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Let the coordinates of point A be (x,y).
Given that Midpoint of AB is (2,-3).
The midpoint formula is:
= > (x1 + x2/2), (y1 + y2)/2
(1).
= > (x + 1)/2 = 2
= > x + 1 = 4
= > x = 3.
(2)
= > (y + 4)/2 = -3
= > y + 4 = -6
= > y = -10.
Therefore the coordinates of point A is (3,-10).
Hope this helps!
Given that Midpoint of AB is (2,-3).
The midpoint formula is:
= > (x1 + x2/2), (y1 + y2)/2
(1).
= > (x + 1)/2 = 2
= > x + 1 = 4
= > x = 3.
(2)
= > (y + 4)/2 = -3
= > y + 4 = -6
= > y = -10.
Therefore the coordinates of point A is (3,-10).
Hope this helps!
siddhartharao77:
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