Question

4) Find the cost of watering a trapezium
field whose parllel sides are 10 cm and 25 cm respactively, the perpandicular distance between them is 15 cm and the rate watering is rupee 4/m².​

Answer 1

Method of Solution:

Given: Parallel sides of trapezium are 10cm and 25 cm and perpendicular distance between the parallel sides is 15 cm.

So, Area of trapezium field =1/2(sum of parallel sides) × (perpendicular distance between them)

Area of Trapezium = 1/2(25+10)×(10)

•°• Area of Trapezium =525/2

Now, According to the Question's Statement!

[the rate watering is rupee 4 per m²]

Required Cost =525/2×4

Hence, Required Cost is Rs 1025.

Answer 2

Step-by-step explanation:

thanks mah answers pls