4. Find the equation of the line intersecting the y- axis at a distance of 3 units above the
origin and tan 2
1 i = , where i is the angle of inclinatio
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line intersecting the y- axis at a distance of 3 units above the
origin.so, we take y - intercept = 3 .
Given, tani = 1/2 ,here i the angle of inclination.
so, tani = 1/2 = slope of required line.
Now, equation of line : y = mx + c
Here m is slope of line and c is y - intercept.
put m = 1/2 and c = 3
So, y = x/2 + 3
2y = x + 6
x - 2y = 6 is the equation of required line
origin.so, we take y - intercept = 3 .
Given, tani = 1/2 ,here i the angle of inclination.
so, tani = 1/2 = slope of required line.
Now, equation of line : y = mx + c
Here m is slope of line and c is y - intercept.
put m = 1/2 and c = 3
So, y = x/2 + 3
2y = x + 6
x - 2y = 6 is the equation of required line
Answered by
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Solution :
It is given that ,
The line intersecting the y-axis at
a distance of 3 units above the
origin and
tan i = 1/2
***************************************
Equation of the line whose
slope = m , y-intercept = c ,
y = mx + c
****************************************
Here ,
slope (m)= tan i = 1/2
y-intercept (c )= 3 ,
Required equation ;
y = ( 1/2 )x + 3
multiply each term with 2 , we get
=> 2y = x + 6
=> x - 2y + 6 = 0
••••
It is given that ,
The line intersecting the y-axis at
a distance of 3 units above the
origin and
tan i = 1/2
***************************************
Equation of the line whose
slope = m , y-intercept = c ,
y = mx + c
****************************************
Here ,
slope (m)= tan i = 1/2
y-intercept (c )= 3 ,
Required equation ;
y = ( 1/2 )x + 3
multiply each term with 2 , we get
=> 2y = x + 6
=> x - 2y + 6 = 0
••••
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