Question

4) Find the HCF of 64,144 and 160 by prime factorisation method.



please help me it's my final exam questions of maths​

Answer 1

Answer:

Step-by-step explanation:

64 = 2 x 2 x 2 x 2 x 2 x 2

144 = 2 x 2 x 2 x 2 x 3 x 3

160 = 2 x 2 x 2 x 2 x 2 x 5

So the common numbers are 2 x 2 x 2 x 2 which is equal to 16

So HCF = 16

Answer 2

Answer:

2|64 3|144 2|160

2|32 2|48 2|80

2|16 2|24 2|40

2|8 2|12 2|20

2|4 2|6 2|10

2|2. 3|3 5|5

1 1 1

H.C.F = 2*2*2*2*2*2

2*2*2*2*3*3

2*2*2*2*2*5

=2*2*2*2

=16