Math, asked by antharambh19, 6 months ago

4.
Find the least number which, when divided by 40, 48
and 56, leaves a remainder of 5 in each case.

Answers

Answered by sanjeevaraya3

0

Answer:

1685

Step-by-step explanation:

40 = 2 × 2 × 2 × 5

48 = 2 × 2 × 2 × 2 × 3

56 = 2 × 2 × 2 × 7

Hence, LCM of 40, 48 and 56 = 1680

Required number = 1680 + 5 = 1685

Answered by chandrika3514

0

Answer:

I think it will help you

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