Question

4. Find the length of a seconds' pendulum at a place
where g = 10 m s-2 (Take it = 3-14).
Ans. 1.0142 m​

Answer 1

Explanation:

For a point mass on a weightless string of length L swinging with an infinitesimally small amplitude, without resistance, the length of the string of a seconds pendulum is equal to L = g/π2 where g is the acceleration due to gravity, with units of length per second squared, and L is the length of the string in the same ...