Question

4. Find the mean, mode and median of the following distribution:
100-120
120-140
140-160
160-180
180-200
Frequency
12
14
8
6
10​

Answer 1

li=140, f1=18, fo=14, f2=6, h=20

li+f1-f2/2f1-fo-f2.h

140+18-14/36-14-6.20

140+4/6.20

140+40/3

140+1.33

141.33

Answer 2

Step-by-step explanation:

Answer:

Perimeter of rectangle is 136 cm.

Step-by-step explanation:

Given :-

Area of rectangle and area of square are equal.

Perimeter of square is 64 cm.

Breadth of rectangle is 4 cm.

To find :-

Perimeter of rectangle.

Solution :-

• First we will find side of square using perimeter.

• Area of square and area of rectangle are equal. So, then we will find length of rectangle using area of rectangle.

• Then, Finally we will find required perimeter.

________________________________

Perimeter of square = 4 × side

\longrightarrow⟶ 64 = 4 × side

\longrightarrow⟶ 64/4 = side

\longrightarrow⟶ side = 16

Side of square is 16 cm

Area of square = Side × Side

\longrightarrow⟶ Area = 16 × 16

\longrightarrow⟶ Area = 256

Area of square is 256 cm².

It is given that,

Area of rectangle is equal to area of square.

So, Area of rectangle is 256 cm².

Area of rectangle = length × breadth

\longrightarrow⟶ 256 = Length × 4

\longrightarrow⟶ 256/4 = Length

\longrightarrow⟶ Length = 64

Length of rectangle is 64 cm.

Now,

Perimeter of rectangle = 2(Length + Breadth)

\longrightarrow⟶ Perimeter = 2 × (64 + 4)

\longrightarrow⟶ Perimeter = 128 + 8

\longrightarrow⟶ Perimeter = 136

Therefore,

Perimeter of rectangle is 136 cm.