Question

4) Find the nature of the roots of the Oudratic
equation 3x^2-4√3x+4=0
​

Answer 1

Answer:

Find the nature of the roots of the quadratic equation 3x2-4√3x+4=0 and hence solve it. ... ∴ D=(b2-4ac)={(-4√3)2-4×3×4}=(48-48)=0. This shows that the given quadratic equation has real and equal roots. Each root =-b2a=4√36=2√33.

or

Here, a= 3, b= – 4√3, c= 4 D = (- 4√3)2 -4(3)(4) = 48 – 48 = 0 It’s seen that D = 0 and hence, the given equation has only 1 real and equal root.Read more on Sarthaks.com - https://www.sarthaks.com/647316/determine-the-nature-of-the-roots-of-the-quadratic-equation-3x-2-43x-4-0

Answer 2

Answer:

roots are real and equal

Step-by-step explanation:

discriminant=

${b}^{2} - 4ac$