Math, asked by aray96rishav, 10 months ago

4. Find the number of coins 0.8 cm in radius and
0.4 cm thick to be melted to form a right circular
cylinder of height 10 cm and 8 cm as radius.
(Hint. The shape of coin is cylindrical).​

Answers

Answered by kambojisha
2

Answer:

Given, radius of cylindrical coin, r = 0.8 m = 80 cm

Height of coin = thickness = 0.4m = 40 cm

Height of cylinder h = 10 cm

Radius of the cylinder, r' = 8 cm

A/Q,

No. Of coins * Volume of 1 coin = Volume of Cylinder

=> N * 22/7 * 80* 80* 40 = 22/7 * 8 *8*10

= > N * 5632/7 = 14080/7

=> N = 14080/5632 = 2.5

Answered by nitish346
2

Answer:

number of coins = 250

Step-by-step explanation:

number of coins × volume of one coin = volume of cylinder

number of coins = volume of cylinder / volume of one coin

= π × r^2 × h / π × r^2 × h

= r^2 × h / r^2 × h

= 8 × 8 × 10 / 0.8 × 0.8 × 0.4

= 640 / 2.56

number of coins = 250

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