Question

4. Find the perimeter of a rectangle whose
length is 3 times its breadth. The breadth
is 10 cm. *
(1 Point)​

Answer 1

Answer:

ANSWER

Let length=lcm, width=bcm

⇒l=3b,Diagonal=810cm

Now, l2+b2=d2⇒(3b)2+b2(810)2⇒10b2=640

⇒b2=64⇒b=64=8cm & l=3b=3×6=24cm

Perimeter=2(l+b)=2(24+8)=64cm

Answer 2

Answer:

• Breadth of the rectangle = 10 cm
• So,the length of the rectangle = 3×10cm = 30cm
• Perimeter of the rectangle = 2×(Length+Breadth)
• 2×(30+10 cm)
• 2×40cm
• 80 cm

Please mark as brainliest answer and follow me :-)