Math, asked by rohan996018, 11 months ago

4), Find the point on X-axis which is
equidistant from P(2, -5) and Q(-2, 9).​

Answers

Answered by Anonymous
5

ʟᴇᴛ ᴛʜᴇ ᴩᴛ ʙᴇ ʀ(x,0)

ᴩʀ=√(2-x)²+(-5)²

=√4+x²-4x+25

=√x²-4x+29

qʀ=√(x+2)²(-9)²

=√x²+4+4x+81

=√x²+4x+85

ᴩq=ᴩʀ

√x²-4x+29=√x²+4x+85

=>x²-4x+29=x²+4x+85 ꜱqᴜᴀʀɪɴɢ ʙᴏᴇᴛʜ ꜱɪᴅᴇꜱ

=>-8x=85-29

=>-8x=56

=>x=-7

ᴛʜᴇ ʀᴇqᴜɪʀᴇᴅ ᴩᴛ ɪꜱ (x,0) ɪᴇ (-7,0)

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