Question

4. Find the point on y-axis, equidistant from two points A(-3,4)and B(3,6) on the same plane​

Answer 1

let the point P be (0, a). As it lies on Y axis its abscissa is to be 0

Now given P is equidistant from A(-3,4) and B(3,6)

This means PA^2 = PB^2

(-3)^2 + (a-4)^2 = (3)^2 + (a - 6)^2

==> a - 4 = + (a - 6) which is not valid

But a - 4 = -(a-6)

==> a - 4 + a - 6 = 0

OR 2 a = 10

So a = 5

(0,5) is equidistant from A and B

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