Question

4. Find the principal on which a simple interest of rupees 55 will be obtained after 9 months at the rate of 11/3% per annum​

Answer 1

$SI= \frac{P×R×T}{100}$

$55 = \frac{P \times 11 \times 9}{3 \times 100}$

$55 = \frac{99P}{300}$

$55 = 0.33p$

$p = 0.33 - 55$

$p = - 54.67$

Answer 2

Step-by-step explanation:

Let the principal amount be Rs. P.

Rate of interest = 11/3 % and time = 9/12 years.

So, Simple interest = P × (11/300) × (9/12) = 55

P = (55 × 12 × 300) / (9 × 11) = Rs. 2000