Question

4. Find the product of(1/2x³ ) × (-10x) × (1/5x²)
and verify the result for x = 1....
I mark brainliest​

Answer 1

ANSWER:

• The product of the given terms = - x⁶.

GIVEN:

• (1/2 x³) × (-10 x) × (1/5 x²)

• x = 1

TO FIND:

• The product of the given terms.

TO VERIFY:

• The result for x = 1.

EXPLANATION:

$\sf \dashrightarrow\dfrac{1}{2} x^3 \times (-10 x) \times \dfrac{1}{5} x^2$

$\sf \dashrightarrow\dfrac{1}{2}( - 10) (x^3) (x)\times \dfrac{1}{5} x^2$

$\sf \dashrightarrow( - 5) x^4 \times \dfrac{1}{5} x^2$

$\sf \dashrightarrow\dfrac{1}{5}( - 5) (x^4) (x^2)$

$\sf \dashrightarrow - x^6$

$\boxed{ \bold{\red{\dfrac{1}{2} x^3 \times (-10 x) \times \dfrac{1}{5} x^2 = - {x}^{6} }}}$

VERIFICATION:

$\sf \leadsto \dfrac{1}{2} x^3 \times (-10 x) \times \dfrac{1}{5} x^2 = - {x}^{6}$

$\textbf{ \pink{Substitute x = 1}}$

$\sf \leadsto \dfrac{1}{2}(1)^3 \times (-10 (1)) \times \dfrac{1}{5} (1)^2 = - {1}^{6}$

$\sf \leadsto \dfrac{1}{2}(1) \times (-10) \times \dfrac{1}{5} (1) = - 1$

$\sf \leadsto \dfrac{1}{2} \times (-10) \times \dfrac{1}{5} = - 1$

$\sf \leadsto \dfrac{1}{10} \times (-10) = - 1$

$\sf \leadsto - 1 = - 1$

HENCE VERIFIED.

Answer 2

$\huge\color{blue}{\underline{\underline{answer\::}}}$

Given :-

• 1/2x ³ × (-10x) × 1/5x²
• x = 1

To find :-

Product of given terms.

To prove :-

The answer = 1

Solution :-

• ½x³ × (-10)x + ⅕x²

• ½ (-10)(x³) (x) × ⅕x²

• (-5)x⁴ × ⅕x²

• ⅕(-5) (x⁴) (x²)

• -x⁶

Now , put x = 1

• ½ (1)³ × (-10) (1) + ⅕ (1)² = -1⁶

• ½ × -10 × ⅕ = -1

• ⅒/10 × -10 = -1

• - 1 = -1

Hence , Verified.