Question

4. Find the product of (34b+ 4a) and (ab + a) and verify the result for a = 2 and
5. Find the products.
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Answer 1

Answer:

and and you can do to our for dinner tomorrow for a bit late for work in progress for you guys have fun at all the best of luck for tomorrow for a bit late for work in progress for you guys have fun at all the best of luck for tomorrow for a bit late for work in progress

Answer 2

Answer:

Product will be 34b²a+34ba+4a²b+4a²

Step-by-step explanation:

1. Now (34b+4a)(ab+a)=34b²a+34ba+4a²b+4a² now put a=2 then it will become 68b²+84b+16=0---eqn( 1) now to make it easier divide both sides by 4 then we get 17b²+21b +4=0 now u can do it by substitution method or factorize it. In my opinion factorize is easier to use so I used factorization method. break the eqn 17b²+17b+4b +4=0 then try to separate the commons then 17b(b+1)+4(b+1)=0 then roots are formed (17b+4) and( b+1) now see which is easier to put in main eqn. Her we use( b+1) =0 then b=-1 will be the outcome and for verification put the value of b=-1 in eqn 1 we get 68-84+16 =0 that is 68 +16-84=0 or 84-84 =0 that is 0=0 hence verified