Question

4. Find the rate of interest p.a. at which ? 30,000 will amount to 2 39,930 in three years, compounding of interest being done annually.​

Answer 1

P=Rs.30,000,T=2years and R=10%

⇒ A=P(1+

100

R

)

T

⇒ A=30000×(1+

100

10

)

2

⇒ A=30000×

10

11

×

10

11

∴ A=Rs.36300

⇒ C.I.=A−P=Rs.36300−Rs.30000=Rs.6300

Answer 2

Answer:

₹6300

${\huge\star} { \tt\blue{6300}}$