Question

4.Find the roots of 4x2 +3x+5=0 by the method of completing square method. ​

Answer 1

Answer:

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(2x)²+2×2x×3/4+(3/4)²‐(3/4)²+5=0

(2x+3/4)²‐9/16+5=0

(2x+3/4)²+71/16=0

(2x+3/4)²=‐71/6<0

but (2x+3/4)² cannot be negative

so the given equation has no real roots

Answer 2

Answer:

$\huge\mathcal\orange{Answer}$

Given equation

4x

2

+3x+5=0

Dividing by 4

4

4x

2

+

4

3x

+

4

5

=0

x

2

+

4

3x

+

4

5

=0

We know that

(a+b)

2

=a

2

+2ab+b

2

Here a=x

2ab=

4

3x

2b=

4

3

b=

8

3

Adding and subtracting (

8

3

)

2

x

2

+

4

3x

+

4

5

+(

8

3

)

2

−(

8

3

)

2

=0

(x+

8

3

)

2

+

4

5

−(

8

3

)

2

=0

(x+

8

3

)

2

=

64

9

−

4

5

(x+

8

3

)

2

=

64

9−80

(x+

8

3

)

2

=

64

−71

Step-by-step explanation:

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