Math, asked by dharam8445088082, 2 months ago

4.
Find the smallest number by which 2890 must be
divided to get a perfect square. Also, find the square
root of the perfect square so obtained.​

Answers

Answered by adityapalaria
2

Answer:

Step-by-step explanation:

(i) 252 = 2 x 2 x 3 x 3 x 7

Here, prime factor 7 has no pair. Therefore 252 must be

divided by 7 to make it a perfect square.

∴ 252 ÷ 7 = 36

And √36 = 2 x 3 = 6

(ii) 2925 = 3 x 3 x 5 x 5 x 13

Here, prime factor 13 has no pair.

Therefore 2925 must be divided by 13

to make it a perfect square.

∴ 2925 ÷ 13 = 225

And √225 = 3 x 5 = 15

(iii) 396 = 2 x 2 x 3 x 3 x 11

Here, prime factor 11 has no pair. Therefore 396 must be

divided by 11 to make it a perfect square.

∴ 396 ÷ 11 = 36

And √36 = 2 x 3 = 6

(iv) 2645 = 5 x 23 x 23

Here, prime factor 5 has no pair. Therefore 2645 must be

divided by 5 to make it a perfect square.

∴ 2645 ÷ 5 = 529

And √529 = 23 x 23 = 23

(v) 2800 = 2 x 2 x 2 x 2 x 5 x 5 x 7

Here, prime factor 7 has no pair. Therefore 2800 must be

divided by 7 to make it a perfect square.

∴ 2800 ÷ 7 = 400

And √400 = 2 x 2 x 5 = 20

Answered by divya003359
0

Answer:

2800=2×2×2×2×5×5×7

Step-by-step explanation:

i think it help you

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