Question

4 Find the smallest number of five digits that can be exactly divided by 60, 90 and 80​

Answer 1

Explanation:

For such types of questions you must know how to get lowest common multiple of numbers i.e. LCM and i am assuming that you know it.

So LCM (60, 80, 90) will be 720.

And for lowest five digit number you should take largest four digit number(i.e. 9999) …..and if the case would be of highest five digit number you should take lowest six digit number(i.e. 100000) …..remember it

Now divide the number by the LCM

9999÷720 THEN remainder will be 639

Take difference of (720–639) = 81

Add it in largest 4 digit number

9999+81 = 10080 will be your answer.

Im case of highest five digit number ….

Divide 100000 by 720 then remainder will be 640

Now in this case you have to subtract this remainder from the largest 6 digitnumber ..

100000–640 = 99360 will be your largest five digit number divisible by 60, 80 and 90.

Hope it helps you.