Question

4. Find the smallest number which when divided by 8, 9, 10, 15, 20 gives a remainder
of 5 every time​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

365

Step-by-step explanation:

LCM of  8, 9, 10, 15, 20 is given by

2 |8,9,10,15.20

2 |4,9,5,15,10

3 |2,9,5,15,5

2 |2,3,5,5,5

3 |1,3,5,5,5

5|1,1,5,5,5

 |1,1,1,1,1

now,

       2 * 2*3*2*3*5 = 365