Question

-4. Find the squares of the following numbers using
the identity (a - b)2 = 1 - 2ab +B
(a) (982)sq. (b) (999)sq. (c)( 495)sq.
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Answer 1

Step-by-step explanation:

(982)^2

(1000-18)^2

(a-b)^2=a^2-2ab+b^2

a=1000

b=18

1000^2-(2*1000*18)+18^2

1000000-36000+324

=964324

(999)^2

(1000-1)^2

(a-b)^2=a^2-2ab+b^2

a=1000

b=1

1000^2-(2*1000*1)+1^2

1000000-2000+1

=998001

(495)^2

(500-5)^2

(a-b)^2= a^2-2ab+b^2

a=500

b=5

500^2-(2*500*5)+5^2

250000-5000+25

=245025

HOPE HELPS YOU ☺️