4: Find the sum of
(1) the first 1000 positive integers (ii) the first n positive integers
pls help fast it's urgent
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Answer:
Sum of first 1000 positive integers=n(n+1)/2
=1000(1000+1)/2
=500(1001)
500500 is the answer for (i)
(ii)Sum of first positive integers=n(n+1)/2
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