Question

4. Find the sum of 35 terms of an arithmetic
progression whose second term is 2 and 7 th
term is 22.​

Answer 1

Answer:

THE SUM OF 35 TERMS WILL BE 2310

Step-by-step explanation:

n=35

2nd term=2. (a+d=2)

7th term=22. (a+6d=22)

so, by simultaneous equation,

a+6d=22

(-)a+(-)d=(-)2

5d=20

d=4

a+d=2

a+4=2

a=-2

S35=S(2a+(n-1)d)

n

S35=35(-4+(34*4))

2

S35=35/2*132

S35=2310

HOPE IT HELPS YOU!