4) Find the sum of first 11 positive numbers which are multiples of 6.
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Answers
Answered by
6
sum of 11 +ve numbers which are multiples of 6
ap formed. -6,12,18, ,,,,,,,,,,,,,66
a-6
n=11
d=6
sn=n/2(as+(n-1)*d
=11/2(2*6+(11-1)*6
=11/2(12+10*6)
=11/2(12+60)
=11/2(72)
=11*36
=396
Answered by
4
sum of 11 +ve numbers which are multiples of 6
ap formed. -6,12,18, ,,,,,,,,,,,,,66
a-6
n=11
d=6
\huge\tt\underline\red{solution}
solution
sn=n/2(as+(n-1)*d
=11/2(2*6+(11-1)*6
=11/2(12+10*6)
=11/2(12+60)
=11/2(72)
=11*36
=396
\huge\tt\underline\purple{thanks}
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