Question

4. Find the sum of first 40 positive integers divisible by 6 also find the sum of first 20

positive integers divisible by 5 or 6.​

Answer 1

Answer:

Positive integers divisible by 6 are 6, 12, 18, 24,…. Since difference is same, it is an AP We need to find sum of first 40 integers We can use formula Sn = /2 (2a + (n – 1) d) Here , n = 40 , a = 6 & d = 12 – 6 = 6 Putting values in formula Sn = /2 (2a + (n – 1) d) Sn = 40/2(2×6+(40−1)×6) Sn = 20 (12 + 39 × 6) Sn = 20 (12 + 234) Sn = 20 × 246 Sn = 4920 Therefore, the sum of first 40 multiples of 6 is 4920

Step-by-step explanation:

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Answer 2

Answer:

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