4) Find the value of 2 sec 10^ Ox cos/o^0
Answers
Answered by
0
Answer:
Given,
(sec
2
10
o
−cot
2
80
o
)
=(sec
2
10
o
−cot
2
(90
o
−10
o
))
=sec
2
10
o
−tan
2
10
o
=1
Hence 1 will be the answer
please mark me as the brainliest....
Similar questions