Question

4: Find the value of √3 cosec 20° – sec 20°.

Answer 1

Answer:

=2(sin20∘3/2−cos20∘1/2)

=2(sin20∘sin60∘−cos20∘cos60∘)

=2(sin20∘cos20∘sin60∘cos20∘−cos60∘sin20∘)

=2(sin20∘cos20∘sin(60∘−20∘))

=2sin20∘cos20∘sin40∘

=2×sin20∘cos20∘2sin20∘cos20

Answer 2

Refer the attachment ❤️