Question

4. Find the value of

(a) 8x + 2y - 3xy + 1/2x^2
for x = -3, y = 5​

Answer 1

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Answer 2

$If \: x = -3 \: and \: y = 5 \: then \\\red{The \:value \: of \:8x+2y-3xy+ \frac{1}{2x^{2}} }$

$= 8 (-3) + 2\times 5 - 3 \times (-3)\times 5 + \frac{1}{2\times (-3)^{2}}$

$= -24 + 10 + 45 + \frac{1}{18}$

$= 31 + \frac{1}{18}$

$= \frac{ 558}{18}$

Therefore.,

$\red{The \:value \: of \:8x+2y-3xy+ \frac{1}{2x^{2}} }$

$\green {= \frac{ 558}{18}}$

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