4.
Find the value of a,if pq2a=(4pq+3q)2-(4pq-3q)2
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Answer:
(4pq+3q)2−(4pq−3q)2=48pq2
LHS=(4pq)2+2(4pq)(3q)+(3q)2−[(4pq)2−2(4pq)(3q)+(3q)2]
=16p2q2+24pq2+9q2−16p2q2+24pq2−9q2
=48pq2
=RHS
LHS=RHS
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