Question

4. Find the value of (b) 4x^4 + x^3 + xy^2 – y^3 +6 for x = -2, y = 5 .​​

Answer 1

Answer:

-113

Step-by-step explanation:

x = -2

y = 5

substituting the values,

4x⁴+x³+xy²-y³+6

= 4(-2)⁴+(-2)³+(-2)(5)²-(5)³+6

= 4(16)+(-8)+(-2)(25)-(125)+6

= 64-8-50-125+6

= -113

Therefore the value of 4x⁴+x³+xy²-y³+6 is -113

Answer 2

Answer:

(-113)

Step-by-step explanation:

4x⁴ + x³ + xy² – y³ +6

Let,

x = -2, y = 5

= 4(-2)⁴ + (-2)³ + (-2)(5)² – (5)³ +6

= 4(16) + (-8) + (-2)(25) - 125 +6

= 64 -8 - 50 -125 + 6

= 70 -183

= (-113)

          Hope it is helpful. Take care.