Question

4) find the value of k so that the quadratic equation has equal roots.
A 2kx - 40x + 25 = 0
b) 2x2 - (K-2) x + 1 = 0
c) (k+3)x²4 2(k+ 3x + 4 =0
211 + 2 x + 1 + p) = 0​

Answer 1

Answer:

(A) a=2k 'b=-40 c=25

therefore D=b^2- 4ac

=(-40)^2-4(2k)25

=1600-200k

=for real and equal root

we required D=0

therefore 1600-200k=0

=200k=1600

=k=1600/200

=k=8

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