Question

4.
Find the value of sin18° cosec54° cosec36° sec72° cos54° cos36º.
(A) 1
(B) O
(C) 2
(D)
CO2-4)

Answer 1

Answer:

1

Step-by-step explanation:

• wkt sinx.cosecx=1
• cosx.secx=1
• sin(90-x)=cosx ,vise versa
• cosec(90-x)=secx,vise versa.
• sec72=cosec18,cosec54=sec36,cosec36=sec54

sin18cosec54cosec36sec72cos54cos36

=sin18sec36sec54cosec18cos54cos36

=(sin18cosec18)(cos54sec54)(cos36sec36)

=1*1*1=1

PLEASE mark the answer as BRAINLIEST. ✍️