Question

4) Find the value of tan? 10° - cot? 80°
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Answer 1

tan(90-∅)=cot(∅)

tan(10°)=cot(90°-10°)=cot(80°)

from the question:

tan(10°) - cot(80°)

=cot(80°) - cot(80°)

=0

Answer 2

The value of expression is $\tan^2 10- \cot^2 80=0$

Step-by-step explanation:

Given : Expression $\tan^2 10- \cot^2 80$

To find : The value of the expression ?

Solution :

Expression $\tan^2 10- \cot^2 80$

Re-write the tan as,

$=\tan^2(90-80)- \cot^2 80$

Using trigonometric value, $\tan(90-\theta)=\cot \theta$

$=\cot^2 80- \cot^2 80$

$=0$

Therefore, the value of expression is $\tan^2 10- \cot^2 80=0$

#Learn more

Which one is correct??

- tan(90 - A) = cotA

- tan(90 - A) = secA

- sec(90 - A) = tan A​

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