Question

4. Find the value of
$5x ^{2} - 3x + 7$
when x =
$\frac{1}{2}$
​

Answer 1

Correct Question:-

Find the value of $5x ^{2} - 3x + 7$ when x = $\frac{1}{2}$

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Answer:-

${\bf{(5×{\frac{1}{2}}^{2}) - (3×\frac{1}{2}) + 7}}$

${\bf{\implies( 5 × \frac{1}{4} )-(\frac{3}{2}) +7}}$

${\bf{\implies( \frac{5-6}{4})+7}}$

${\bf{\implies \frac{-1+28}{4}}}$

${\bf{\implies 6\frac{1}{4}}}$

Answer 2

$\huge \star \; \bf \underbrace {ANSWER} \: \star$

‣ Given :

→ $\sf {p(x) \: = \: 5x^{2} - 3x + 7}$

→ $\sf {x \: = \: \frac{1}{2}}$

‣ To Find :

$\textsf {The value}$

‣ Solution :

$\sf {Put \: \; x \; = \; \frac{1}{2} \: \; in \: \; 5x^{2} - 3x + 7}$

→ $\sf {5x^{2} - 3x + 7}$

→ $\sf {= \: 5 (\frac{1}{2})^{2} - 3 (\frac{1}{2}) + 7}$

→ $\sf {= \: 5 × \frac{1}{4} - 3 × \frac{1}{2} + 7}$

→ $\sf {= \: \frac{5}{4} - \frac{3}{2} + 7}$

→ $\sf {= \: \frac {5 - 6 + 28}{4}}$

→ $\sf {= \: \frac {27}{4}}$

$\implies \sf {\underline {Hence, \: the \: answer \: is \: \frac{27}{4}.}}$

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