Question

4. Find the value of x for which (x + 2), 2x, (2x + 3) are three consecutive
terms of an AP.
(CBSE 2009C]​

Answer 1

Answer:

the value of x for which (x+2) , 2x, (2x+3) is x=1

Answer 2

$\bf{\underline{Question:-}}$

Find the value of x for which (x + 2), 2x, (2x + 3) are three consecutive terms of an AP.

$\bf{\underline{Solution:-}}$

Let ,

• take an A.P of terms a, b, c
• The arithmetic mean is b

$\sf → b = \frac{a+c}{2}$

$\bf{\underline{Here:-}}$

$\sf → a= x + 2$

• $\sf b= 2x$
• $\sf c= 2x + 3$
• On substituting the values in the formula

$\bf{\underline{We\:get:-}}$

$\sf → 2x=x+2+2x+\frac{3}{2}$

$\sf→ 2x=3x+\frac{5}{2}$

$\sf→ 4x=3x+5$

$\sf → 4x - 3x = 5$

$\sf → X=5$

$\bf{\underline{Hence:-}}$

• The value of x is 5