Question

4. Find the value of x?
(x-2) (x+3) = x²-4​

Answer 1

Answer:

(x-2)(x+3)=x²-4

x²+3x-2x-6=x²-4

-5x=-4

x=4/5

Answer 2

❥ Rationale :

$(x - 2)(x + 3) = {x}^{2} - 4$

↝ By multiplying the terms within brackets ,

${x}^{2} + 3x - 2x - 6 = {x}^{2} - 4$

↝ Now By simplifying the common terms ,

${x}^{2} + x - 6 = {x}^{2} - 4$

↝ Bringing all terms to LHS , we get

${x}^{2} + x - 6 - {x}^{2} + 4 = 0$

$\implies \: x - 6 + 4 = 0$

$\implies \: x - 2 = 0$

$\bf \: \implies \: x = 2$

Therefore The value of x = 2