Question

4.
Find the zero of the polynomial in each of the following cases:
(1) p(x)=x+5
(ii) p(x) = x-5
(iii) p(x) = 2x + 5
(iv) p(x) = 3x - 2
(v) p(x) = 3x
(vi) p(x) = ax, a =
(vii) p(x) = cx + d. c#0, c, d are real numbers.​

Answer 1

Answer:

the answer is given below in image

Answer 2

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(i) We have, p(x) = x + 5. Since, p(x) = 0

⇒ x + 5 = 0

⇒ x = -5.

Thus, zero of x + 5 is -5.

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