Math, asked by harjashandeepk, 2 months ago

4. Find the zero of the polynomial in each of the following cases:
(ptx)=x+ 5
(ii) p(x)=r-5
(im) px) = 2x+5
(iv) p(x)=3x-2
(v) ptx) = 32
(vi) ptr) = ax = 0
(vii) p(x) = c++ d.c*0.c, d are real numbers​

Answers

Answered by asahilthakur
1

Answer:

(i) x+5 = 0

=> x = -5

(ii) x-5 = 0

=> x = 5

(iii) 2x+5 = 0

=> 2x = -5

=> x = -5/2

(iv) 3x-2 = 0

=> 3x = 2

=> x = 2/3

(vi) ax = 0

=> x = 0/a

0 divided by any non-zero number is 0.

=> x = 0

(vii) cx+d = 0

=> cx = -d

=> x = -d/c

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