Math, asked by gillkhush44, 19 days ago

4. Find the zeroes of the polynomial a. P(x)=3x-2
b. P(x)=(x-2)2-(x+2)

Answers

Answered by survemanali19
1

Answer:

Put p(x)=0, For finding zeroes of the given polynomial

Put p(x)=0, For finding zeroes of the given polynomial ⟹x

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2 −3x+2=0

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2 −3x+2=0⟹x

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2 −3x+2=0⟹x 2

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2 −3x+2=0⟹x 2 −x−2x+2=0

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2 −3x+2=0⟹x 2 −x−2x+2=0⟹x(x−1)−2(x−1)=0

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2 −3x+2=0⟹x 2 −x−2x+2=0⟹x(x−1)−2(x−1)=0⟹(x−2),(x−1)=0

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2 −3x+2=0⟹x 2 −x−2x+2=0⟹x(x−1)−2(x−1)=0⟹(x−2),(x−1)=0⟹x−2=0 , x−1=0

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2 −3x+2=0⟹x 2 −x−2x+2=0⟹x(x−1)−2(x−1)=0⟹(x−2),(x−1)=0⟹x−2=0 , x−1=0⟹x=2 , x=1

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2 −3x+2=0⟹x 2 −x−2x+2=0⟹x(x−1)−2(x−1)=0⟹(x−2),(x−1)=0⟹x−2=0 , x−1=0⟹x=2 , x=1⟹2,1 are zeroes of the equation p(x)=x

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2 −3x+2=0⟹x 2 −x−2x+2=0⟹x(x−1)−2(x−1)=0⟹(x−2),(x−1)=0⟹x−2=0 , x−1=0⟹x=2 , x=1⟹2,1 are zeroes of the equation p(x)=x 2

Put p(x)=0, For finding zeroes of the given polynomial ⟹x 2 −3x+2=0⟹x 2 −x−2x+2=0⟹x(x−1)−2(x−1)=0⟹(x−2),(x−1)=0⟹x−2=0 , x−1=0⟹x=2 , x=1⟹2,1 are zeroes of the equation p(x)=x 2 −3x+2.

hope you get the answer..

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