Question

4, Find two consecutive positive integers, sum of whose squares is 365,​

Answer 1

Let the numbers be x and (x+1)

according to the question, x^2 + (x+1)^2=365

2x^2 + 2x - 364 = 0

x^2 + x - 182 = 0

x = 13 and -14

since they are positive integers therefore, x=13 and the other number= x+1=14