Question

(4) First increase then decrease
A particle executes simple harmonic motion
with an angular velocity and maximum
acceleration of 3.5 rad/sec. and 7.5 m/s²
respectively. Amplitude of the oscillations is:
[AIPMT-99)
(1) 0.28 m
(2) 0.36 m
(3) 0.53 m
(4) 0.61 m

Answer 1

Answer:

a=-w^2* x

a=w^2* a1

3.5=56.25 a1

35/562.5=a1

0.06 * 2pi m

.36m=amplitude

Explanation: